40x^2+70x=0

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Solution for 40x^2+70x=0 equation: 



40x^2+70x=0

a = 40; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·40·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*40}=\frac{-140}{80}
=-1+3/4
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*40}=\frac{0}{80}
=0
$

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